How many grams in 5.033x10^24 atoms of Oxygen?

To find how many grams are in \(5.033 \times 10^{24}\) atoms of oxygen, we can follow these steps:

1. **Find the molar mass of oxygen**:  
   Oxygen has a molar mass of approximately 16 grams per mole (g/mol).

2. **Use Avogadro's number**:  
   Avogadro's number is \(6.022 \times 10^{23}\) atoms per mole. This tells us how many atoms are in 1 mole of oxygen.

3. **Convert atoms to moles**:  
   To convert the given number of atoms to moles, divide the number of atoms by Avogadro's number:  
   \[
   \text{Moles of oxygen} = \frac{5.033 \times 10^{24} \text{ atoms}}{6.022 \times 10^{23} \text{ atoms/mol}}
   \]

4. **Convert moles to grams**:  
   Once we know how many moles we have, we can multiply by the molar mass (16 g/mol) to find the mass in grams.

Let's calculate this:

\[
\text{Moles of oxygen} = \frac{5.033 \times 10^{24}}{6.022 \times 10^{23}} \approx 8.36 \text{ moles}
\]

Now, multiply by the molar mass:

\[
\text{Mass of oxygen} = 8.36 \text{ moles} \times 16 \text{ g/mol} = 133.76 \text{ grams}
\]

Thus, \(5.033 \times 10^{24}\) atoms of oxygen weigh approximately **133.76 grams**.

Would you like more details or have any questions?

Here are 5 related questions for further understanding:
1. How would the mass change for a different number of atoms?
2. What is the role of Avogadro's number in these calculations?
3. How do you convert from grams to atoms of a substance?
4. Why is the molar mass of oxygen 16 g/mol?
5. How does the concept of moles help in chemistry?

**Tip:** Always make sure to use the correct molar mass depending on the element's molecular form, like O\(_2\) for molecular oxygen.

Learn how to convert 5.033x10^24 atoms of oxygen into grams using stoichiometry. This detailed solution covers the use of Avogadro's number, molar mass, and the conversion process. Ideal for students in Grades 10-12.

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